Write a program that prints X with probability=0.1, Y with probability=0.3, and Z with probability=0.6

Source Code in java (ProbGen.java)

import java.util.Random;

class ProbGen

{

                public static void main(String ar[])

                {

                /*

                no_x,no_y,no_z are variables to count the no. of x,y and

                z respectevily in the output of the test.

                */

                 int i,no_x=0,no_y=0,no_z=0;

                 float rand=0;

                 for(i=0;i<10000;i++)

                 {

                 /*

                  Random.nextFloat() generates a float from 0.0 (inlcusive)

                  to 1.0 (exclusive).

                 */

                 rand = new Random().nextFloat(); // [0;1)

                 if(rand>=0.0 && rand<0.1)

                   {

                   System.out.print("x");

                   no_x++;

                   }

                   else if(rand>=0.1 && rand<0.4)

                    {

                     System.out.print("y");

                                 no_y++;

                    }else

                                 {

               System.out.print("z");

                                 no_z++;

                     }

                 }

                System.out.println("\nNo of x="+no_x+"\nNo of y="+no_y+"\nNo of Z="+no_z);

                }

}          

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Source Code in C

#include <stdlib.h>

#include <stdio.h>

int main(void)

{

   int i,no_x=0,no_y=0,no_z=0;

   float p;

   clrscr();

   printf("Ten random numbers from 0 to 99\n\n");

   for(i=0; i<10000; i++)

   {

      p= (float)(rand() % 10)/10;

      if(p>=0 && p<0.1)

       {printf("x"); no_x++;}

      else

      if(p>=0.1 && p<=0.4)

{printf("y");no_y++;}

      else

{printf("z");no_z++;}

   }

     printf("\nNo fo x=%d\No of y=%d\nNo of z=%d",no_x,no_y,no_z);

      getch();

   return 0;

}